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s^2-17s+66=0
a = 1; b = -17; c = +66;
Δ = b2-4ac
Δ = -172-4·1·66
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-5}{2*1}=\frac{12}{2} =6 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+5}{2*1}=\frac{22}{2} =11 $
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